11=5x^2+13x+5

Solution for 11=5x^2+13x+5 equation:

11=5x^2+13x+5

We move all terms to the left:

11-(5x^2+13x+5)=0

We get rid of parentheses

-5x^2-13x-5+11=0

We add all the numbers together, and all the variables

-5x^2-13x+6=0

a = -5; b = -13; c = +6;
Δ = b2-4ac
Δ = -132-4·(-5)·6
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-17}{2*-5}=\frac{-4}{-10}
=2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+17}{2*-5}=\frac{30}{-10}
=-3
$